Check 2 strings are following patterns

# Check 2 strings are following patterns

January 31, 2023 Name
Moch Lutfi
@kaptenupi

## Problem

Given an array `strings`, determine whether it follows the sequence given in the `patterns` array. In other words, there should be no `i` and `j` for which `strings[i] = strings[j]` and `patterns[i] ≠ patterns[j]` or for which `strings[i] ≠ strings[j]` and `patterns[i] = patterns[j]`.

Example

• For `strings = ["cat", "asu", "asu"]` and `patterns = ["a", "b", "b"]`, the output should be
`solution(strings, patterns) = true`;
• For `strings = ["cat", "asu", "anjing"]` and `patterns = ["a", "b", "b"]`, the output should be
`solution(strings, patterns) = false`.

Input/Output

• [input] array.string strings

An array of strings, each containing only lowercase English letters.

Guaranteed constraints:
`1 ≤ strings.length ≤ 10^5`,
`1 ≤ strings[i].length ≤ 10`.

• [input] array.string patterns

An array of pattern strings, each containing only lowercase English letters.

Guaranteed constraints:
`patterns.length = strings.length`,
`1 ≤ patterns[i].length ≤ 10`.

• [output] boolean

Return `true` if `strings` follows `patterns` and `false` otherwise.

## Solution

• This solution uses two maps to store the relationship between a string and a pattern.
• For each string in strings, the solution checks if a pattern has already been assigned to that string and if the assigned pattern is the same as the current pattern in patterns.
• If not, the function returns false.
• The same is done for the pattern to string mapping.
• If no inconsistencies are found, the function returns true.
`func solution(strings []string, patterns []string) bool { stringToPattern := make(map[string]string) patternToString := make(map[string]string) for i, str := range strings { pattern, strExists := stringToPattern[str] string, patternExists := patternToString[patterns[i]] if strExists && pattern != patterns[i] || patternExists && str != string { return false } stringToPattern[str] = patterns[i] patternToString[patterns[i]] = str } return true}`